- Saturday Morn - April 20, 2019

? Explanation of report features  
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Field strength:  Mean: 1313 MP  Geomean: 762 MP
(based on 18 players)
★ ★ ★  Masterpoint Winners  ★ ★ ★
Partnership Pct Rank MP
Josh Rosenbluth - Ken Ellenberger 62.99 1st A 1.50
Christopher Gillmon - Mark Robbins 57.42 2nd A 1.13
Dagmar Ragnow - Nancy Hall 55.07 3rd A 0.84
Anne Conn - Louise Shaffer 53.68 4th A 0.67
EVENT>Open Pairs               |SESSION>Saturday Morn|SECTION> C
------------------------,------ ------------,-------- --------------------------
DATE>April 20, 2019     |CLUB NO.>131102    | 04/20/2019 14:51
---------------------,-- ------------------- -------------,---------------------
DIR> Tom Ciacio      |RATING>Club Masterpoint (100%, 80%, 80% Open)|MOVEMENT>ONE WINNER
------------,-------- ,-------------------------,--------- ---------------------
AVE>   36.0 |TOP>   3 |MP LIMITS>None/2000/900  |CLUB>Ventura Unit Bridge Club
------------ --------- ------------------------- -------------------------------
PAIRS IN STRAT A=9/B=6/C=3                       ,---,-------------------------,------,---------,
-------------------------------------------------|   |           Section       |      |Section  |
No Name                   Name                   |Flt|Rnk-A|Rnk-B|Rnk-C| Score | Pct  |Awards   |
------------------------------------------------- --- ----- ----- ----- ------- ------ ---------
 1 Anne Cline             Maurine Moore            A    .     .     .     34.29  47.63
 2 Teresa Moore           Sheila Moore             C    .     .     .     30.30  42.08
 3 Larry Pelletier        Barry Brenner            B    .     .     .     32.38  44.97
 4 Christopher Gillmon    Mark Robbins             C    2     2     1     41.34  57.42  1.13(A)
 5 Louise Shaffer         Anne Conn                C    4     .     .     38.65  53.68  0.67(A)
 6 Josh Rosenbluth        Ken Ellenberger          B    1     1     .     45.35  62.99  1.50(A)
 7 Ilona Smith            Dick Zizic               A    .     .     .     31.63  43.93
 8 Mike Gaddis Jr         Irene Petroff            B    .     .     .     29.90  41.53
10 Dagmar Ragnow          Nancy Hall               A    3     .     .     39.65  55.07  0.84(A)
                                          Totals                         323.49

Hands and Results
1 ♠Q986
K42
Q7
♣KQ96
Dlr: North
Vul: None
♠A42
AQT53
83
♣J84
♠T53
9876
A942
♣A2
♠KJ7
J
KJT65
♣T753
12
118
9
Double Dummy Makes
NS: 3♣ 2 2♠  ♥5 NT6
EW: 2 1NT  ♣4 ♦5 ♠5
LoTT: 17 - 17 = 0
Par: +100 3*-EW-1
  N-S   E-W    N-S    E-W   Contract
  110          2.83   0.17  3♣ N      C7-Smith-Zizic vs C3-Pelletier-Brenner
   50          0.83   2.17  3 W -1   C6-Rosenbluth-Ellenberger vs C5-Shaffer-Conn
   50          0.83   2.17  3 W -1   C10-Ragnow-Hall vs C8-Gaddis Jr-Petroff
2 ♠AKJ5
QT94
AQJ5
♣J
Dlr: East
Vul: N-S
♠7
A76
K763
♣K8643
♠T92
83
T984
♣A975
♠Q8643
KJ52
2
♣QT2
18
104
8
Double Dummy Makes
NS: 1 4 5♠ 3NT  ♣6
EW: 1♣  ♦6 ♥2 ♠2 NT3
LoTT: 18 - 18 = 0
Par: +650 5♠-NS
  N-S   E-W    N-S    E-W   Contract
  650          2.17   0.83  4♠ S +1   C6-Rosenbluth-Ellenberger vs C5-Shaffer-Conn
  650          2.17   0.83  4♠ S +1   C7-Smith-Zizic vs C3-Pelletier-Brenner
  620          0.17   2.83  4♠ S      C10-Ragnow-Hall vs C8-Gaddis Jr-Petroff

Craig Hemphill Hand Analysis
WestNorthEastSouth
  PassPass
Pass1Pass1
Pass4All pass 

If South were not a passed hand, North might contemplate bidding 4, a game forcing spade raise with a singleton club, but with the original pass, it is wildly unlikely to construct a hand making slam -- not impossible, but it would require Q, AK, K, which would have been opened, or Q, a singleton heart, K, and A. a difficult parlay.

4 is the practical bid, and after losing the round aces, eleven tricks are easily captured.



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3 ♠T754
T53
72
♣AT32
Dlr: South
Vul: E-W
♠AQ63
AQ42
63
♣Q54
♠9
87
AK9854
♣KJ98
♠KJ82
KJ96
QJT
♣76
4
1411
11
Double Dummy Makes
NS:  ♣2 ♦2 ♥4 ♠5 NT2
EW: 5♣ 5 3 2♠ 3NT
LoTT: 16 - 16 = 0
Par: -600 3NT-EW/5-EW/5♣-EW
  N-S   E-W    N-S    E-W   Contract
  100          2.83   0.17  3N W -1   C10-Ragnow-Hall vs C8-Gaddis Jr-Petroff
        110    1.50   1.50  3♣ E      C7-Smith-Zizic vs C3-Pelletier-Brenner
        600    0.17   2.83  3N W      C6-Rosenbluth-Ellenberger vs C5-Shaffer-Conn

Craig Hemphill Hand Analysis
WestNorthEastSouth
   Pass
1Pass1Dbl
Pass12Pass
2NTPass3NTAll pass

A bit aggressive by East, but the odds must favor the attempt, with the likelihood of many diamond tricks.

And so it is. Aggression, within reason, pays.



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4 ♠532
J863
AKJ86
♣K
Dlr: West
Vul: Both
♠AKJT4
A754
5
♣JT7
♠6
KQT9
Q7
♣AQ9843
♠Q987
2
T9432
♣652
12
1313
2
Double Dummy Makes
NS: 1  ♣0 ♥0 ♠1 NT0
EW: 6♣ 6 5♠ 2NT  ♦5
LoTT: 19 - 19 = 0
Par: -1430 6-EW
  N-S   E-W    N-S    E-W   Contract
        620    2.50   0.50  4♠ W      C1-Cline-Moore vs C3-Pelletier-Brenner
        620    2.50   0.50  5♣ E +1   C5-Shaffer-Conn vs C2-Moore-Moore
        650    1.00   2.00  4 E +1   C7-Smith-Zizic vs C6-Rosenbluth-Ellenberger
        680    0.00   3.00  4 W +2   C8-Gaddis Jr-Petroff vs C4-Gillmon-Robbins

Craig Hemphill Hand Analysis
WestNorthEastSouth
1Pass2Pass
2Pass3Pass
3Pass4Pass
4Pass4Pass
PassPass  

Some might bid this slam, but not many, and it depends on a finesse for the club king plus a guess for the heart jack. It's a two-way finesse, pure and simple, and declarer will actually be helped by the defense's leading two rounds of diamonds. That will make the technician play hearts as follows, having been shortened in trumps in the West hand: K, then a heart to the A, revealing all, and prevailing in the quest for twelve tricks when the K pops.



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5 ♠K
AQ763
T7
♣AQ964
Dlr: North
Vul: N-S
♠J
JT4
AKJ3
♣87532
♠Q8764
K82
Q964
♣J
♠AT9532
95
852
♣KT
15
108
7
Double Dummy Makes
NS: 1♣ 3 1♠ 1NT  ♦5
EW: 2  ♣4 ♥4 ♠5 NT5
LoTT: 17 - 15 = +2
Par: +140 3-NS
  N-S   E-W    N-S    E-W   Contract
  150          3.00   0.00  4 W -3   C8-Gaddis Jr-Petroff vs C4-Gillmon-Robbins
  140          1.50   1.50  3 N      C5-Shaffer-Conn vs C2-Moore-Moore
  140          1.50   1.50  2 N +1   C1-Cline-Moore vs C3-Pelletier-Brenner
  100          0.00   3.00  3 W -2   C7-Smith-Zizic vs C6-Rosenbluth-Ellenberger

Craig Hemphill Hand Analysis
WestNorthEastSouth
 1Pass1
Pass2Pass2
PassPassPass 

South's sequence shows no interest in advancing toward game, and fewer than three hearts. With three or more hearts, a direct raise would have been appropriate with single raise values, regardless of spade length. So North should subside in the 5-2 fit. While the K is a good card, there is nothing to be done with it after diamonds are cashed.

The defense is entitled to two diamonds and two hearts. If declarer leads the 9 from dummy, West must cover to preserve those two tricks, because East holds the 8!!



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6 ♠-
AQ86
K543
♣AJ742
Dlr: East
Vul: E-W
♠QJ54
J973
AJ
♣K95
♠76
KT54
QT987
♣Q8
♠AKT9832
2
62
♣T63
14
127
7
Double Dummy Makes
NS: 3♣ 3♠  ♦6 ♥5 NT6/5
EW: 1/2 1/2NT  ♣4 ♦6 ♠4
LoTT: 17 - 16 = +1
Par: +140 3♠-NS
  N-S   E-W    N-S    E-W   Contract
  140          3.00   0.00  3♠ S      C1-Cline-Moore vs C3-Pelletier-Brenner
  110          2.00   1.00  2♠ S      C5-Shaffer-Conn vs C2-Moore-Moore
         50    1.00   2.00  3♠ S -1   C7-Smith-Zizic vs C6-Rosenbluth-Ellenberger
        100    0.00   3.00  4♠* S -1  C8-Gaddis Jr-Petroff vs C4-Gillmon-Robbins
7 ♠Q96
873
AQT9
♣K84
Dlr: South
Vul: Both
♠T74
KT965
5
♣JT75
♠K532
42
KJ874
♣92
♠AJ8
AQJ
632
♣AQ63
11
47
18
Double Dummy Makes
NS: 3♣ 3 3 3♠ 4/3NT
EW:  ♣4 ♦4 ♥4 ♠4 NT3
LoTT: 13 - 14 = -1
Par: +630 4NT-S
  N-S   E-W    N-S    E-W   Contract
  600          2.17   0.83  3N S      C6-Rosenbluth-Ellenberger vs C3-Pelletier-Brenner
  600          2.17   0.83  3N N      C10-Ragnow-Hall vs C1-Cline-Moore
  200          0.17   2.83  2 E -2   C2-Moore-Moore vs C4-Gillmon-Robbins

Craig Hemphill Hand Analysis
WestNorthEastSouth
   1
Pass1Pass2NT
Pass3NTAll pass 

North should avoid bidding 2NT without a heart stopper if there is a logical alternative -- there is! Bid 1 and let South declare.

Oh dear! That concept should have worked well, but the computer gives a different conclusion. Did you notice that NORTH can make ten tricks in notrump, while South can make just nine? What's that about?

Whenever you see that a different number of tricks can be made depending on who declares, be sure that there is some sort of vulnerability that can only be exploited by the defense specifically with the opening lead. Here that lead is the 5 from West, an unlikely lead. That will relieve East of pressure and an effective endplay, having to hold TWO diamond honors plus length, along with the K. The opening lead lessens that pressure, according to the computer.

Fear not. Humans don't lead singletons against notrump contracts in suits bid by the opponents. West will lead a heart and then South can make ten tricks, according to the computer. Wait! Where are those ten tricks? Two spades after the finesse works, two hearts, three clubs, and two diamonds make just nine. Where is the tenth? Perhaps a squeeze? Lead the Q, forcing the K to cover, and then West has to hold the Tx, along with the clubs and the hearts? Yes, surely that would work. But when East has just two hearts it is easier than that. Just finesse in diamonds and play the A when East returns the lead, then another diamond. When declarer wins and runs diamonds, West is rather finished, whether the spade menace had been transferred or not. The guard squeeze (holding the T works well, too!).

A bit difficult, admittedly, and maybe a bit double-dummy, but an interesting exercise, and showing the analysis will forestall inquiries requesting an explanation how it might be accomplished.



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8 ♠954
K7
AKJ75
♣942
Dlr: West
Vul: None
♠Q63
AT643
432
♣T5
♠T72
QJ92
QT
♣AK76
♠AKJ8
85
986
♣QJ83
11
612
11
Double Dummy Makes
NS: 2♣ 3 3♠ 2NT  ♥5
EW: 2  ♣5 ♦3 ♠4 NT4
LoTT: 17 - 17 = 0
Par: +140 3♠-NS
  N-S   E-W    N-S    E-W   Contract
  110          2.17   0.83  2♠ S      C6-Rosenbluth-Ellenberger vs C3-Pelletier-Brenner
  110          2.17   0.83  3 N      C10-Ragnow-Hall vs C1-Cline-Moore
   50          0.17   2.83  3 W -1   C2-Moore-Moore vs C4-Gillmon-Robbins
9 ♠732
Q962
Q62
♣AT6
Dlr: North
Vul: E-W
♠AQT96
A
K4
♣QJ973
♠5
K753
JT9
♣K8542
♠KJ84
JT84
A8753
♣-
8
167
9
Double Dummy Makes
NS: 1  ♣2 ♦6 ♠4/5 NT4
EW: 5♣ 2♠ 2/3NT  ♦6 ♥6
LoTT: 18 - 18 = 0
Par: -600 5♣-EW
  N-S   E-W    N-S    E-W   Contract
        130    2.83   0.17  3♣ W +1   C6-Rosenbluth-Ellenberger vs C3-Pelletier-Brenner
        170    0.83   2.17  4♣ W +2   C2-Moore-Moore vs C4-Gillmon-Robbins
        170    0.83   2.17  3♣ W +3   C10-Ragnow-Hall vs C1-Cline-Moore
10 ♠AQ84
J72
Q32
♣A64
Dlr: East
Vul: Both
♠96
AKT965
J94
♣87
♠KT52
43
AT76
♣KQJ
♠J73
Q8
K85
♣T9532
13
813
6
Double Dummy Makes
NS:  ♣6 ♦4 ♥4 ♠6 NT5
EW: 1♣ 2/3 3 1♠ 2NT
LoTT: 15 - 16 = -1
Par: -140 3-EW
  N-S   E-W    N-S    E-W   Contract
  100          2.83   0.17  2 W -1   C1-Cline-Moore vs C6-Rosenbluth-Ellenberger
        110    1.50   1.50  2 W      C10-Ragnow-Hall vs C2-Moore-Moore
        140    0.17   2.83  3 W      C7-Smith-Zizic vs C4-Gillmon-Robbins
11 ♠K85
QT4
QT
♣Q8732
Dlr: South
Vul: None
♠32
K972
J854
♣AKJ
♠T6
8653
AK92
♣954
♠AQJ974
AJ
763
♣T6
9
127
12
Double Dummy Makes
NS: 2♣ 2♠ 1NT  ♦5 ♥5
EW: 2 2  ♣5 ♠5 NT6
LoTT: 16 - 17 = -1
Par: +100 3*-EW/3*-EW-1
  N-S   E-W    N-S    E-W   Contract
  170          2.83   0.17  2♠ S +2   C10-Ragnow-Hall vs C2-Moore-Moore
  140          1.50   1.50  3♠ S      C1-Cline-Moore vs C6-Rosenbluth-Ellenberger
        100    0.17   2.83  3♠ S -2   C7-Smith-Zizic vs C4-Gillmon-Robbins
12 ♠6
6
K6543
♣KJT864
Dlr: West
Vul: N-S
♠QT8543
K754
AQT
♣-
♠AJ9
QJ98
72
♣9752
♠K72
AT32
J98
♣AQ3
7
118
14
Double Dummy Makes
NS: 4♣ 3/4 2NT  ♥4 ♠3
EW: 3 3♠  ♣3 ♦3 NT5
LoTT: 19 - 18 = +1
Par: +100 4♠*-EW/4*-EW-1
  N-S   E-W    N-S    E-W   Contract
  130          2.83   0.17  4♣ S      C10-Ragnow-Hall vs C2-Moore-Moore
        420    0.83   2.17  4♠ W      C1-Cline-Moore vs C6-Rosenbluth-Ellenberger
        420    0.83   2.17  4♠ W      C7-Smith-Zizic vs C4-Gillmon-Robbins
13 ♠T95
T854
QT9
♣KJ3
Dlr: North
Vul: Both
♠Q32
J2
AKJ64
♣T97
♠K4
Q96
752
♣AQ652
♠AJ876
AK73
83
♣84
6
1111
12
Double Dummy Makes
NS:  ♣4 ♦4 ♥6 ♠6 NT5
EW: 3♣ 3 1/- 1/-♠ 2/1NT
       ♥7/6 ♠7/6
LoTT: 15 - 16 = -1
Par: -120 2NT-E
  N-S   E-W    N-S    E-W   Contract
  300          3.00   0.00  5 W -3   C10-Ragnow-Hall vs C3-Pelletier-Brenner
  100          2.00   1.00  3 W -1   C2-Moore-Moore vs C7-Smith-Zizic
        200    1.00   2.00  3♠ S -2   C8-Gaddis Jr-Petroff vs C5-Shaffer-Conn
        800    0.00   3.00  3♠* S -3  C4-Gillmon-Robbins vs C6-Rosenbluth-Ellenberger
14 ♠7543
AK74
T3
♣AK5
Dlr: East
Vul: None
♠-
T65
J75
♣QJT9876
♠K86
QJ32
AKQ84
♣4
♠AQJT92
98
962
♣32
14
415
7
Double Dummy Makes
NS: 5♠ 2NT  ♣5 ♦5 ♥6
EW: 2♣ 2 1  ♠2 NT3
LoTT: 19 - 18 = +1
Par: +450 5♠-NS
  N-S   E-W    N-S    E-W   Contract
  420          3.00   0.00  4♠ S      C2-Moore-Moore vs C7-Smith-Zizic
  300          2.00   1.00  5♣* W -2  C4-Gillmon-Robbins vs C6-Rosenbluth-Ellenberger
  200          1.00   2.00  3♠ S +2   C8-Gaddis Jr-Petroff vs C5-Shaffer-Conn
  170          0.00   3.00  2♠ S +2   C10-Ragnow-Hall vs C3-Pelletier-Brenner
15 ♠Q
AK7653
AK54
♣85
Dlr: South
Vul: N-S
♠943
JT82
T7
♣QT63
♠JT876
-
J83
♣AK942
♠AK52
Q94
Q962
♣J7
16
39
12
Double Dummy Makes
NS: 3/2 4 1♠ 2NT  ♣5
EW: 2♣  ♦0 ♥1 ♠6 NT3
LoTT: 18 - 18 = 0
Par: +500 5♣*-EW-3
  N-S   E-W    N-S    E-W   Contract
  620          2.50   0.50  4 N      C2-Moore-Moore vs C7-Smith-Zizic
  620          2.50   0.50  4 N      C8-Gaddis Jr-Petroff vs C5-Shaffer-Conn
  170          1.00   2.00  3 N +1   C10-Ragnow-Hall vs C3-Pelletier-Brenner
        100    0.00   3.00  5 N -1   C4-Gillmon-Robbins vs C6-Rosenbluth-Ellenberger
16 ♠AKQ75
T83
KQ2
♣98
Dlr: West
Vul: E-W
♠T2
KJ752
AT6
♣KT4
♠963
A
98543
♣6532
♠J84
Q964
J7
♣AQJ7
14
114
11
Double Dummy Makes
NS: 2♣ 2 2♠ 3NT  ♦6
EW:  ♣5 ♦6 ♥5 ♠4 NT4
LoTT: 14 - 16 = -2
Par: +400 3NT-NS
  N-S   E-W    N-S    E-W   Contract
  140          3.00   0.00  3♠ N      C2-Moore-Moore vs C1-Cline-Moore
  110          2.00   1.00  2♠ N      C10-Ragnow-Hall vs C4-Gillmon-Robbins
         50    0.50   2.50  4♠ N -1   C3-Pelletier-Brenner vs C8-Gaddis Jr-Petroff
         50    0.50   2.50  4♠ N -1   C5-Shaffer-Conn vs C7-Smith-Zizic
17 ♠85
T952
752
♣9643
Dlr: North
Vul: None
♠AJT3
83
AJT98
♣75
♠K976
AKQ7
KQ43
♣8
♠Q42
J64
6
♣AKQJT2
0
1017
13
Double Dummy Makes
NS: 1♣  ♦1 ♥2 ♠0 NT1
EW: 6 4 6♠ 1NT  ♣6
LoTT: 19 - 19 = 0
Par: -980 6♠-EW
  N-S   E-W    N-S    E-W   Contract
        230    3.00   0.00  3♠ E +3   C3-Pelletier-Brenner vs C8-Gaddis Jr-Petroff
        420    2.00   1.00  5 E +1   C2-Moore-Moore vs C1-Cline-Moore
        480    0.50   2.50  4♠ W +2   C10-Ragnow-Hall vs C4-Gillmon-Robbins
        480    0.50   2.50  4♠ E +2   C5-Shaffer-Conn vs C7-Smith-Zizic

Craig Hemphill Hand Analysis
WestNorthEastSouth
 Pass12
Dbl341Dbl
42Pass42Pass
4Pass4NTPass
53Pass5All pass
  1. Both majors, game values
  2. Control toward slam, clearly!
  3. No trump queen

A rather nice auction, really. West makes a Negative Double , having a safe landing spot back in diamonds if there is no spade fit, and East's 4 shows both majors and game forcing values. Then 4 cannot be a signoff, for surely there is a major suit fit. Ergo, 4 is a control bid. Now let's find out which major -- 4 offers, 4 corrects, and East takes the invitation extended by 4 to inquire toward slam. Off an ace and missing the trump queen means that the odds are against the slam. Signoff.

Yet the strong likelihood is that twelve tricks will be made, for declarer will be inclined to play first the honor in trumps from the short hand (K97 remaining, after the second club is ruffed), and then take the trump finesse. It works! Those who bid the slam without the mechanism to determine that the trump queen will be successful, wondering what the problem was.

Sometimes too much knowledge is detrimental to success.



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18 ♠T8742
5
JT3
♣KQ82
Dlr: East
Vul: N-S
♠AKJ
QT74
964
♣965
♠96
J632
Q875
♣J43
♠Q53
AK98
AK2
♣AT7
6
104
20
Double Dummy Makes
NS: 4♣ 3 2 4♠ 3NT
EW:  ♣3 ♦4 ♥5 ♠3 NT4
LoTT: 15 - 16 = -1
Par: +620 4♠-NS
  N-S   E-W    N-S    E-W   Contract
  620          2.00   1.00  4♠ S      C3-Pelletier-Brenner vs C8-Gaddis Jr-Petroff
  620          2.00   1.00  4♠ S      C5-Shaffer-Conn vs C7-Smith-Zizic
  620          2.00   1.00  4♠ S      C10-Ragnow-Hall vs C4-Gillmon-Robbins
        100    0.00   3.00  3N S -1   C2-Moore-Moore vs C1-Cline-Moore

Craig Hemphill Hand Analysis
WestNorthEastSouth
  Pass2NT
Pass3Pass3
Pass3NTPass4
All pass   

West counts three trump tricks and hopes to find partner with a trick, setting the contract.

Alas -- good thing West refrained from a speculative double!



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19 ♠KQ8
42
QJT93
♣972
Dlr: South
Vul: E-W
♠JT6
QJ98
A
♣AQJT6
♠973
T653
K72
♣854
♠A542
AK7
8654
♣K3
8
153
14
Double Dummy Makes
NS: -/1♣ 3 2♠  ♣5/7 ♥5 NT6
EW: 1 1NT  ♣6 ♦3 ♠4
LoTT: 16 - 17 = -1
Par: +110 2♠-NS/3-NS
  N-S   E-W    N-S    E-W   Contract
  130          2.50   0.50  3 S +1   C3-Pelletier-Brenner vs C2-Moore-Moore
  130          2.50   0.50  3 S +1   C6-Rosenbluth-Ellenberger vs C8-Gaddis Jr-Petroff
  110          1.00   2.00  3 S      C10-Ragnow-Hall vs C5-Shaffer-Conn
         50    0.00   3.00  4 S -1   C1-Cline-Moore vs C7-Smith-Zizic
20 ♠T9
K96
KJ63
♣K987
Dlr: West
Vul: Both
♠652
JT532
Q7
♣Q43
♠K83
Q4
AT942
♣A65
♠AQJ74
A87
85
♣JT2
10
513
12
Double Dummy Makes
NS: 4♣ 3 3 5♠ 5/4NT
EW:  ♣2 ♦4 ♥4 ♠2 NT2
LoTT: 15 - 14 = +1
Par: +660 5NT-S
  N-S   E-W    N-S    E-W   Contract
  400          3.00   0.00  2 E -4   C6-Rosenbluth-Ellenberger vs C8-Gaddis Jr-Petroff
  300          2.00   1.00  2 E -3   C10-Ragnow-Hall vs C5-Shaffer-Conn
  210          1.00   2.00  1N N +4   C3-Pelletier-Brenner vs C2-Moore-Moore
  200          0.00   3.00  2♠ S +3   C1-Cline-Moore vs C7-Smith-Zizic
21 ♠T2
A76
Q9
♣KJT983
Dlr: North
Vul: N-S
♠A753
K953
AT4
♣Q5
♠K986
842
K863
♣42
♠QJ4
QJT
J752
♣A76
10
136
11
Double Dummy Makes
NS: 3♣ 1 1 1♠ 3NT
EW:  ♣4 ♦5/6 ♥6 ♠6 NT4
LoTT: 15 - 17 = -2
Par: +600 3NT-NS
  N-S   E-W    N-S    E-W   Contract
  130          2.50   0.50  2♣ N +2   C3-Pelletier-Brenner vs C2-Moore-Moore
  130          2.50   0.50  2♣ N +2   C10-Ragnow-Hall vs C5-Shaffer-Conn
  110          1.00   2.00  2♣ N +1   C1-Cline-Moore vs C7-Smith-Zizic
  100          0.00   3.00  2♠ E -2   C6-Rosenbluth-Ellenberger vs C8-Gaddis Jr-Petroff
22 ♠32
KJT875
K6
♣J98
Dlr: East
Vul: E-W
♠QT76
2
85432
♣AK7
♠A954
Q3
QJ9
♣QT65
♠KJ8
A964
AT7
♣432
8
911
12
Double Dummy Makes
NS: 3 2NT  ♣5 ♦4 ♠4
EW: 2/1♣ 2 2♠  ♥4 NT4
LoTT: 17 - 18 = -1
Par: +140 3-NS
  N-S   E-W    N-S    E-W   Contract
         50    3.00   0.00  3♠ S -1   C2-Moore-Moore vs C8-Gaddis Jr-Petroff
        100    2.00   1.00  2♠ S -2   C10-Ragnow-Hall vs C6-Rosenbluth-Ellenberger
        150    1.00   2.00  3♠ S -3   C5-Shaffer-Conn vs C1-Cline-Moore
        800    0.00   3.00  4N* N -4  C4-Gillmon-Robbins vs C3-Pelletier-Brenner
23 ♠62
T642
AKQT76
♣3
Dlr: South
Vul: Both
♠JT94
953
832
♣T97
♠Q5
AKJ7
J954
♣AKJ
♠AK873
Q8
-
♣Q86542
9
119
11
Double Dummy Makes
NS: 1♣ 1  ♥6 ♠6 NT6
EW: 1/-NT
       ♣6/4 ♦6 ♥6 ♠6/4 NT7/6
LoTT: 13 - 14 = -1
Par: -90 1NT-E
  N-S   E-W    N-S    E-W   Contract
  140          3.00   0.00  3 N      C5-Shaffer-Conn vs C1-Cline-Moore
    PASS       2.00   1.00  Pass Out  C2-Moore-Moore vs C8-Gaddis Jr-Petroff
        100    1.00   2.00  4 N -1   C4-Gillmon-Robbins vs C3-Pelletier-Brenner
        200    0.00   3.00  4 N -2   C10-Ragnow-Hall vs C6-Rosenbluth-Ellenberger

Craig Hemphill Hand Analysis
WestNorthEastSouth
   1
Pass3!1? 
  1. Invitational with six diamonds, nine to eleven HCP, no spade fit.

GRRRRR!

East should pass, of course, for a double would be for takeout. That's OK. South will regret bidding at all, and only a pass by South will garner any matchpoints at all. Any further bid will be punished by East, who will then be rewarded for patience.

The problems started when South decided to open 1. Better to have opened in South's longest suit with 1, the six-bagger, then 1 after either red suit, in the event East passed, intending to bid spades again to show 5??6 pattern -- that should have been the initial plan.. In any event, opening 1 would solve the systemic problem that will happen as described at a very few tables.

SOMEBODY is likely to get in trouble on this hand. Will it be NS or EW? That probably will vary from table to table, and an easy prediction is that scores will be all over the place.



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24 ♠KQ542
QJ862
9
♣AT
Dlr: West
Vul: None
♠JT9876
93
2
♣J753
♠A
74
QJ86543
♣KQ9
♠3
AKT5
AKT7
♣8642
12
212
14
Double Dummy Makes
NS: 2♣ 1 6 2♠ 4NT
EW:  ♣4 ♦6 ♥1 ♠5 NT3
LoTT: 18 - 17 = +1
Par: +980 6-NS
  N-S   E-W    N-S    E-W   Contract
  480          2.50   0.50  4 N +2   C4-Gillmon-Robbins vs C3-Pelletier-Brenner
  480          2.50   0.50  4 N +2   C5-Shaffer-Conn vs C1-Cline-Moore
  450          1.00   2.00  4 N +1   C10-Ragnow-Hall vs C6-Rosenbluth-Ellenberger
  430          0.00   3.00  3N S +1   C2-Moore-Moore vs C8-Gaddis Jr-Petroff

Craig Hemphill Hand Analysis
WestNorthEastSouth
Pass13Dbl
Pass3Pass4
Pass4Pass5
Pass6Pass6
All pass   

South cannot (well, some WILL) bid 4NT with the South hand in the auction after the Negative Double and slam-interest cue/control 4 bid if North "signs off" with 4.. If South incorrectly bids 4NT and obtains the answer "1," does North have AKQ42 QJ843 9 76? Or the actual hand? No, Asking for aces won't do the job when North has one ace.

South's sequence is highly suggestive of slam, but clearly denies a club control. Our North, with both first and third round control of clubs, heeds the call and bids the slam.

This is not a pure sequence, for North could have Axx and only four hearts, when slam would fail, but it comes closer to science than 4NT, which would miss this one.

Is there a solution to bidding the hand properly? YES! North's 4 bid was a mistake! Despite having only 12 HCP, the marvelous distribution and known heart fit should spring to mind the Losing Trick Count. North has a five loser hand, a known heart fit, a partner who has made a slam try in hearts. What on earth is North waiting for. NORTH should launch 1430 Roman Keycard Blackwood with 4NT, for it is NORTH who has the pattern and honors that will benefit from the answer to the question, "how many key cards do you have, partner?" The concerns about losing clubs that pestered South don't even rise to North's level of consciousness. A bit of visualization for North should be sufficient to place South with just the right cards, subject to confirmation with 4NT: Remember that the 4 bid denied both the A and AK, so does not South rate highly to have AK AK? Just confirm and move to slam!!

Easley Blackwood taught that it is the hand with second and third round controls that should be asking with his convention. North's present hand is a poster for his principle.



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25 ♠AJ8
T42
AT
♣KQ974
Dlr: North
Vul: E-W
♠54
AJ63
KJ5
♣AT83
♠T732
Q87
Q862
♣52
♠KQ96
K95
9743
♣J6
14
134
9
Double Dummy Makes
NS: 3♣ 1 1 3♠ 2NT
EW:  ♣4 ♦6 ♥6 ♠4 NT4
LoTT: 15 - 14 = +1
Par: +140 3♠-NS
  N-S   E-W    N-S    E-W   Contract
  300          2.83   0.17  2 E -3   C10-Ragnow-Hall vs C7-Smith-Zizic
   90          0.83   2.17  2♣ N      C5-Shaffer-Conn vs C4-Gillmon-Robbins
   90          0.83   2.17  2♣ N      C8-Gaddis Jr-Petroff vs C1-Cline-Moore
26 ♠J84
K5
K742
♣9732
Dlr: East
Vul: Both
♠A95
QT76
AJT
♣A54
♠K
A982
Q863
♣QT86
♠QT7632
J43
95
♣KJ
7
1511
7
Double Dummy Makes
NS:  ♣3 ♦3 ♥3 ♠6 NT4
EW: 4♣ 4 4 1♠ 3NT
LoTT: 16 - 17 = -1
Par: -620 4-EW
  N-S   E-W    N-S    E-W   Contract
        600    2.83   0.17  3N W      C5-Shaffer-Conn vs C4-Gillmon-Robbins
        620    0.83   2.17  4 W      C8-Gaddis Jr-Petroff vs C1-Cline-Moore
        620    0.83   2.17  4 W      C10-Ragnow-Hall vs C7-Smith-Zizic
27 ♠AK54
87
J9763
♣J2
Dlr: South
Vul: None
♠T92
AKQ6
KQT8
♣K6
♠Q8763
3
5
♣AQ9543
♠J
JT9542
A42
♣T87
9
178
6
Double Dummy Makes
NS:  ♣2 ♦5/6 ♥5 ♠3 NT3
EW: 3♣ 1 1 4♠ 4NT
LoTT: 16 - 16 = 0
Par: -430 4NT-EW
  N-S   E-W    N-S    E-W   Contract
   50          2.83   0.17  4♠ W -1   C10-Ragnow-Hall vs C7-Smith-Zizic
        460    0.83   2.17  3N W +2   C5-Shaffer-Conn vs C4-Gillmon-Robbins
        460    0.83   2.17  3N W +2   C8-Gaddis Jr-Petroff vs C1-Cline-Moore